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OpenStudy (vijay):
-3/2
OpenStudy (anonymous):
Can you explain how you got that cuz i wanna be able to do the other problems i have
OpenStudy (anonymous):
Do you just substitute?
OpenStudy (vijay):
differentiate then substitute
OpenStudy (anonymous):
differentiate?
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OpenStudy (vijay):
yes, derivative means u have to differentiate
OpenStudy (anonymous):
How do you differentiate?
OpenStudy (vijay):
f(x) = 6 x^(-1)
df/dx = (-1)* 6 *X^(-2)
OpenStudy (vijay):
now substitute x= -2
OpenStudy (vijay):
which is give -3/2
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OpenStudy (anonymous):
sorry to keep saying thisbut i'm still confused. as tohow you got this "df/dx = (-1)* 6 *X^(-2)"
OpenStudy (vijay):
f(x) = 6 * x^(-1)
OpenStudy (vijay):
now if u do the differentiation
OpenStudy (agent0smith):
Use the power rule to differentiate... multiply by the power, and reduce the power by one, or: \[\Large \frac{ d }{ dx } x^n = n x ^{n-1}\]
\[ \Large f(x) =\frac{ 6 }{ x} = 6x^{-1}\]
So multiply by the power (-1) and reduce the power by one (-1 -1 = -2):\[\Large \frac{ d }{ dx} (6x^{-1}) = -1*6 x^{-2}\]
OpenStudy (ybarrap):
Following @agent0smith, for this problem, n = 1 and x is in the denominator:
\[6*\frac{ d}{ dx } (1/x^{n}) = 6\frac{ d}{ dx } x^{-n} = -n *6 x^{-n -1}=6\frac{-n}{x^{n+1}}\]
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