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Find all solutions to the equation. 2cos(theta) + sqrt 2 = 0
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let's represent cos theta by x, can you find value of x? \[2x+\sqrt 2=0\]
-√2/2
Good or it can be simplified as \[\frac{-1}{\sqrt 2}\]
oh ok
We have now \[\cos \theta=\frac{-1}{\sqrt 2}\]
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do you know the value of theta if cos theta =1 /sqrt 2
mmm no
what's cos 45?
0.52532198881 ?
i just plugged that in my calculator :/
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Hmmm, there might be another way than just calculator.
oh i see.
how to I write the answer in radians or in terms of pie?
|dw:1375940748496:dw|
It's gotta be half or a right angle to work.
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A right angle in radians is \(2\pi / 4 = \pi / 2\). So what is half of that?
There are 4 right angles in a full revolution.
half of π/2? i don't know
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