Find the range of values of x for which the equation in y, 2x^2 − 3xy + y^2 − 5x + 11 =0 will have real roots. Find also for what values of y the equation in x will have real roots.
Complete the square? Or quadratic equation!
complete the square is better i think
So if you let \(x\) be the variable then \(\color{red}a, \color{blue}b, \text{ and } \color{green} c\) are:\[ \color{red} {2}x^2 + \color{blue}{ (-3y-5)}x +\color{green}{ y^2+11 } \]
ooh? hmm i think i can solve this now. Gimme a min
i got discriminant to equal to y^2 + 30y - 63
Is that what you got for \(b^2 - 4ac\)?
now i have \[y = -15 \pm 12\sqrt{2}\]
For real roots we want \(b^2-4ac \geq 0\)
yea
Well, you want to know when the equation of \(y\) is above \(0\).
Roots will only help you know when it changes from positive to negative.
ok i got both my y things. How do we find the x ones?
Okay so for what values of \(y\) does \(x\) have real roots?
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