Question

-(5/w+2) = -8 - (7/w-1)

Answer 1

-(5/w+2) = -8 - (7/w-1)
-(5 +2 W) = -8 W - (7-W)
-(5 +2 W) = -7 W - 7
-5 +5 W) = - 7
W = - 7/5

Answer 2

there should be more than one solution

Answer 3

\[-\frac{5}{w+2} = -8 -\frac{7}{w-1}\]
\[-\frac{5}{w+2} = -\left(8 +\frac{7}{w-1}\right)\]
\[\frac{5}{w+2} = \left(8 +\frac{7}{w-1}\right)\]
\[\frac{5}{w+2} = \frac{8(w-1)+7}{w-1}\]
\[\frac{5}{w+2} = \frac{8w-8+7}{w-1}\]
\[\frac{5}{w+2} = \frac{8w-1}{w-1}\]
\[5(w-1) = (8w - 1)(w+2)\]
\[\frac{w-1}{w+2}=\frac{8w-1}{5}\]
\[\frac{w+2-3}{w+2}=\frac{8w-1}{5}\]
\[\frac{w+2}{w+2}- \frac{3}{w+2}=\frac{8w-1}{5}\]
\[1- \frac{3}{w+2}=\frac{8w-1}{5}\]
\[1- \frac{3}{w+2}=\frac{5 + 8w-6}{5}\]
\[1- \frac{3}{w+2}=\frac{5}{5} + \frac{8w-6}{5}\]
\[1- \frac{3}{w+2}=1 + \frac{8w-6}{5}\]
\[-\frac{3}{w+2}=\frac{8w-6}{5}\]
\[-(3)(5) = (8w-6)(w+2)\]
\[-15 = 8w^2 + 16w - 6w - 12\]
\[-15 = 8w^2 + 10w - 12\]
\[0 = 8w^2 + 10w + 3\]
\[0 = 8w^2 + 6w + 4w + 3\]
\[0 = 2w(4w + 3) + 1(4w + 3)\]
\[0=(4w+3)(2w + 1)\]
Finish the rest

Answer 4

the man

Answer 5

Is it
-(5/w+2) = -8 - (7/w-1)
or
-[5/(w+2)] = -8 - [7/(w-1)]
because they are different answers.

Answer 6

The latter

Answer 7

If it is as written then it should go like this...
-(5/w + 2) = -8 -(7/w - 1)
-5/w - 2 = -8 + (-7/w) +1
-5/w - 2 = -7 + (-7/w)
-5/w + 5 = -7/w
-5 + 5w = -7
5w = -2
w = -2/5 (or 0.4)

Answer 8

I'm pretty confident that is as I posted. I guess we'll never know.

Answer 9

Well, either way now they have both.