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Algebra 24 Online
OpenStudy (dls):

The maximum value of this = (M say ) ?

OpenStudy (dls):

\[\Huge 3^x + 5^x -9^x+15^x-25^x\]

OpenStudy (dls):

Options: 3<M<5 0<M<2 9<M<25 5<M<9

OpenStudy (anonymous):

what is the range of x?

OpenStudy (dls):

not given

OpenStudy (anonymous):

We could differentiate and find where f'(x) = 0 but that would take a while to do lol.. @DLS

OpenStudy (anonymous):

obviously...looking at t..for any +ve value of x ..the result will be negative ..so we have to use the least value of x.try x=0...so we get 3-2=1. op.b} bro ;)

OpenStudy (dls):

@genius12 a^x can never be =0 i thought on that

OpenStudy (anonymous):

@dls anything raised to - infinity is zero

OpenStudy (dls):

NO.

OpenStudy (dls):

\[\Huge (25352)^{\infty} \neq 0\]

OpenStudy (anonymous):

i said minus infinity :)

OpenStudy (dls):

oops misread that :P

OpenStudy (dls):

\[\Huge (0.241212)^{-\infty} \neq 0\] still

OpenStudy (dls):

you can't generalize it^

OpenStudy (anonymous):

anyway my answer is b} (i posted above)

OpenStudy (dls):

Actually it is correct

OpenStudy (anonymous):

;)

OpenStudy (dls):

logic seems correct!

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