Solve the inequality: -x+3>7 I need someone to show me step by step how to solve this. I will give you a medal.
I know the answer, so all i need is to learn how to solve it.
Well, you need to get x on one side, by itself, of the inequality. We do this by moving things that are with x to the other side of the inequality. You have to do opposite operations to do that. If you have a +3, you minus 3 from both sides. If you have 3x, you divide both sides by 3, all of the opposites you can do to get x by itself. So to start, we get the +3 away from x. Since this is a + 3, you have to subtract 3, from both sides, to remove it. \[-x + 3 > 7\] \[-x + 3 -3 > 7 - 3\] \[-x > 4\] Does that first step make sense?
yes
now you have to switch the sign right?
Alright then. Now for the last step I personally say we have two options, simply because this is an inequality. So to get that negative away from x, we have to divide both sides by -1. But when you divide or multiply both sides of an inequality by a negative number, the inequality has to flip in the opposite direction. \[-x > 4\] \[\frac{ -x }{ -1 } > \frac{ 4 }{ -1 }\] \[x < -4\] Now if you feel like you might forget to flip the inequality, you can always do this: \[-x>4\] \[-x+x>4+x\] \[0>4+x\] \[-4>-4+4+x\] \[-4>x\] Of course this isnt necessary, but it is a way to get rid of the negative without worrying ab out forgettign to flip the signs around.
anytime you multiply or divide you switch your signs
@Maxicat , i thought you only switch your signs if your dividing both sides by a negative
Only if you multiply or divide by a negative.
oh ok
by a neg. sorry
you doing 5.06 flvs?
yup,
ditto lol.
ave you done the collaboration thing for algebra, i havent
have*
Yeah the easiest way to do it is sign sign up for the live lesson, then your done. Live lessons count as collaborative.
do you know how to sign up?
oh yea, so i did that already,
i use to go to all the live lessons
your good to go then, you met the criteria
oh ok thanks, math is my worst subject, everything else im good with, if you need any help you could just message me if you want
what grade you in?
9th
ok thanks, you too
our welcome, im in 11th, so just message if you need help :)
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