Question

can anybody please help me with this?

Answer 1

Start by factoring each term into prime numbers.

Answer 2

\[(\sqrt{72} +\sqrt{26})\sqrt{13}\]

Answer 3

Simplify the square roots - so you can combine them.

Answer 4

for \[\sqrt{72}\] I simplified it to \[6\sqrt{2}\]. but for square root of 26 I don't know how:(

Answer 5

What are the factors of 26?

Answer 6

2 x 13

Answer 7

So, re-write the expression:
\[(6\sqrt2 +\sqrt13\sqrt2)\sqrt{13}\]
Then distribute. You could have distributed first, but this method keeps the numbers smaller.

Answer 8

How do I distribute? :(

Answer 9

The term that is outside the parenthesis should be multiplied by each term inside the parenthesis.

Answer 10

\(x(a+b) = ax + bx\)

Answer 11

for the first term is \[6 \sqrt{2}\] correct?

Answer 12

That is the first term. Now multiply it by \(\sqrt{13}\).
\(\sqrt{x} \times \sqrt{y} = \sqrt{xy}\)

Answer 13

and the second term is 13\[\sqrt{2}\] correct?

Answer 14

but I did multiply

Answer 15

\(6\sqrt{2} \times\sqrt{13} + \sqrt{13} \times \sqrt{2}\times \sqrt{13}\)

Answer 16

First term is \(6\sqrt{2}\) the second term is \(\sqrt{13}\sqrt{2}\)

Answer 17

is that the answer? Do I need to simplify more... or ?

Answer 18

You need to multiply. I think you did multiply the second term correctly to get \(13\sqrt{2}\) but you still need to multiply the first term by \(\sqrt{13}\).