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@ilfy214 @Isaiah.Feynman @amistre64 @Hero @mathstudent55 help pleaseee
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expand it out and complete a square
how
well, those are pretty basic algebra processes: FOIL to expand and squareing half of the x term to complete a square
or, define the zeros and split the difference
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x=4, and x=-2 are the zeros of this: 1 is the middle so (x-1) has to pertain to the vertex
y = a(x-1)^2 + k when x=1, whats the product for k? (1-4)(1+2) = -3(3) = -9 y = a(x-1)^2 - 9
\[y=(x-4)(x+2)\] \[y=x ^{2}-2x-8\] \[y=(x ^{2}-2x+1)-8-1\] \[y=(x-1)^{2}-9\] There's how you complete the square
the a is spurious at this point since x*x = x^2 has gives us 1
@BangkokGarrett whats the vertex?
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