Question

@ilfy214 @Isaiah.Feynman @amistre64 @Hero @mathstudent55 help pleaseee

Answer 1

expand it out and complete a square

Answer 2

how

Answer 3

well, those are pretty basic algebra processes: FOIL to expand and squareing half of the x term to complete a square

Answer 4

or, define the zeros and split the difference

Answer 5

x=4, and x=-2 are the zeros of this: 1 is the middle so (x-1) has to pertain to the vertex

Answer 6

y = a(x-1)^2 + k

when x=1, whats the product for k?

(1-4)(1+2) = -3(3) = -9

y = a(x-1)^2 - 9

Answer 7

\[y=(x-4)(x+2)\]
\[y=x ^{2}-2x-8\]
\[y=(x ^{2}-2x+1)-8-1\]
\[y=(x-1)^{2}-9\]
There's how you complete the square

Answer 8

the a is spurious at this point since x*x = x^2 has gives us 1

Answer 9

@BangkokGarrett whats the vertex?