Question

write the equation in point slope form.
is perpemdicular to y= - 3/4 x +4 and passes through point (2, -3)??

Answer 1

@kelliegirl33 ??

Answer 2

mind if i helped?

Answer 3

i dont care??

Answer 4

you take it Mousam

Answer 5

oh ok... i thought since he tagged you, you were gonna help him...

Answer 6

broderick.....If I were you, I wouldn't be rude to people, such as jim_thompson...he has many friends

Answer 7

hes all yours Mousam

Answer 8

I guess the first thing to notice is that the equation y=(-3/4)x +4 has the gradient (-3/4). An interesting feature of perpendicular lines is that the multiple of the gradients of both lines equals to -1. Knowing that we can calculate the gradient of this prependicular line by doing the following
(-3/4)x=-1
x=(4/3)
this means that the gradient of a line perpendicular to y=(-3/4)x +4 has the gradient of (4/3)

Answer 9

now that we know the gradient of the perpendicular line, we can use the equation (y-y1) = m(x-x1) to get the equation of a line with gradient 'm' that goes throuhg the point (x1,y1)

Answer 10

since we are trying to find out the equation of the perpendicular line, we can subsitute the gradient and the point that it goes through in to the equation to get
y-(-3) = (4/3)(x-2)
y+3=(4/3)x - (8/3)
y=(4/3)x-(17/3)

Answer 11

that is it... the equation of the perpendicular line is y=(4/3)x-(17/3)

Answer 12

is that answer in point slope lol @Mousam

Answer 13

it is the standard form for writing any linear graph. y=mx+c

Answer 14

you can multiply both left hand side and right and side by 3 to get
3y=4x-17 (if that helps...)

Answer 15

point slope is y - y1 = m(x - x1)

Answer 16

@kelliegirl33 do you have to simplify it from then?

Answer 17

cause i did..

Answer 18

yeah @Mousam it has to be in point slope!! we are trying to find the eqaution of the line

Answer 19

i have done it in point slope...

Answer 20

if you look at my comment with 3 lines of equation in the end... the point slope form is the second-last line...

Answer 21

no...you already gave the answer....you just did more then you had to do...point slope for this is : y -(-3) = 4/3(x - 2) or y + 3 = 4/3(x - 2)

Answer 22

oh... i apologize... in my country, we dont give equation of a linear graph in y-y1=m(x-x1) form. We give it in y=mx+c form...

Answer 23

you did good Mousam :)

Answer 24

For that, I sincerely apologize...

Answer 25

you have no need to apologize

Answer 26

good job @Mousam i gave you a medal for all the help you gave! job well done! and you to @kelliegirl33! :)

Answer 27

thank you broderick....just try not to be rude to people.....that will get you nowhere