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Mathematics 15 Online
OpenStudy (anonymous):

find the total area of the regular pyramid https://media.glynlyon.com/g_geo_2012/8/groupi75.gif

jhonyy9 (jhonyy9):

hi capitana so this a complex problem what is this 6 ?

OpenStudy (anonymous):

the slant area

jhonyy9 (jhonyy9):

slant height ,yes ?

OpenStudy (anonymous):

*slant height

jhonyy9 (jhonyy9):

so do you know what figure is the base ?

jhonyy9 (jhonyy9):

with one side of 4

jhonyy9 (jhonyy9):

how many sides are there in the base ?

jhonyy9 (jhonyy9):

six sides so what is the name of geometricaly corp with six sides ?

OpenStudy (anonymous):

yes the hexagon

jhonyy9 (jhonyy9):

square or pentagon ? no yes right hexagon

OpenStudy (anonymous):

for the perimeter i got 24 and i believe 6 is to be the slant height, and the base will be 16

jhonyy9 (jhonyy9):

but you ned calculi again area of base

jhonyy9 (jhonyy9):

what is this 16 ?

jhonyy9 (jhonyy9):

so the base is formed by six equilateral triangle yes ?

OpenStudy (anonymous):

yes. i got the sixteen by multiplying the sides of the base because i figured that it would be how i would get B

jhonyy9 (jhonyy9):

no you will get area of the base calciling area of an equilateral triangle and multiplie it by six

jhonyy9 (jhonyy9):

how you calculi area of an equilateral triangle with sides 4 ?

OpenStudy (anonymous):

do you just multiply 4 by 3 since all sides are equal?

jhonyy9 (jhonyy9):

no becasue you know that area of a triangle is equal bae time height divide 2

jhonyy9 (jhonyy9):

so than the height of an equlateral triangle you need calculi it

OpenStudy (anonymous):

ok, that's where i start to get stuck, finding the height. do i need the Pythagorean theorem?

jhonyy9 (jhonyy9):

|dw:1376002752803:dw|

jhonyy9 (jhonyy9):

how you get AF using pythagora ?

jhonyy9 (jhonyy9):

so this is easy

OpenStudy (anonymous):

do i use c^2=a^2+b^2?

jhonyy9 (jhonyy9):

c is hypothenuse and a,b sides

jhonyy9 (jhonyy9):

let a = AF so than how you get AF ?

jhonyy9 (jhonyy9):

c^2=a^2+b^2 just subtract from both sides b^2

jhonyy9 (jhonyy9):

so and will get the a^2 yes but you need to calculi the a so this mean that a= sqrt (....) sqrt what you will get subtracting b^2 from both sides ok ?

jhonyy9 (jhonyy9):

come on ,this is easy

jhonyy9 (jhonyy9):

a^2 = c^2 -b^2 a = sqrt(c^2 -b^2) ok ? so now just substitute numericaly

jhonyy9 (jhonyy9):

a = sqrt(16-4) =sqrt (12) = 2sqrt3 right ?

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