find the total area of the regular pyramid https://media.glynlyon.com/g_geo_2012/8/groupi75.gif
hi capitana so this a complex problem what is this 6 ?
the slant area
slant height ,yes ?
*slant height
so do you know what figure is the base ?
with one side of 4
how many sides are there in the base ?
six sides so what is the name of geometricaly corp with six sides ?
yes the hexagon
square or pentagon ? no yes right hexagon
for the perimeter i got 24 and i believe 6 is to be the slant height, and the base will be 16
but you ned calculi again area of base
what is this 16 ?
so the base is formed by six equilateral triangle yes ?
yes. i got the sixteen by multiplying the sides of the base because i figured that it would be how i would get B
no you will get area of the base calciling area of an equilateral triangle and multiplie it by six
how you calculi area of an equilateral triangle with sides 4 ?
do you just multiply 4 by 3 since all sides are equal?
no becasue you know that area of a triangle is equal bae time height divide 2
so than the height of an equlateral triangle you need calculi it
ok, that's where i start to get stuck, finding the height. do i need the Pythagorean theorem?
|dw:1376002752803:dw|
how you get AF using pythagora ?
so this is easy
do i use c^2=a^2+b^2?
c is hypothenuse and a,b sides
let a = AF so than how you get AF ?
c^2=a^2+b^2 just subtract from both sides b^2
so and will get the a^2 yes but you need to calculi the a so this mean that a= sqrt (....) sqrt what you will get subtracting b^2 from both sides ok ?
come on ,this is easy
a^2 = c^2 -b^2 a = sqrt(c^2 -b^2) ok ? so now just substitute numericaly
a = sqrt(16-4) =sqrt (12) = 2sqrt3 right ?
Join our real-time social learning platform and learn together with your friends!