Question

solve each equation for 0≤x≤2π:

sin x= √3 cos x

explain why the trig equation is not an identity.

Answer 1

first of all, the trig equation is not an identity because the value of 'x' can be found.
(cosx)^2+(sinx)^2=1 is an identity because no matter what you do, the value of x cannot be found

Answer 2

\[sinx=(\sqrt{3})cosx\]\[\frac{ sinx }{ cosx } = \sqrt{3}\]\[tanx=\sqrt{3}\]

Answer 3

do you follow me?

Answer 4

no Mousam :(

Answer 5

oh... where did i lose you?

Answer 6

the explanation or the working out?

Answer 7

the working out

Answer 8

oh ok.. do you get my explanation for why that is an equation, not an identity?

Answer 9

ya i understand that. What i dont get is how is 3 square root between 0<2<pi?

Answer 10

so your question is \[sinx=(\sqrt{3})cosx\]

Answer 11

what does 0≤x≤2π mean?

Answer 12

oh... you've misunderstood the question.... we have to find out values of X between 0<x<2pi

Answer 13

woah... did you just start this topic in class?

Answer 14

do you know what 2pi is?

Answer 15

yaa