Question

PLEASE HELP!!! ill give medal

What is the equation of the line that passes through the points (−2, 3) and (2, 7)?

x − y = −1

x − y = −2

x − y = − 5

x − y = − 6

Answer 1

@kelliegirl33

Answer 2

@kelliegirl33

Answer 3

I messed up

Answer 4

For points \((x_1, y_1)\) and \((x_2, y_2) \), the equation of the line through them is:

\(y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}( x - x_1) \)

Answer 5

slope(m) = (y2 - y1) /(x2 - x1)
m = (7 - 3) / (2 - (-2)
m = 4/(2 + 2)
m = 4/4
m = 1

point slope formula :
y - y1 = m(x - x1)
y - 7 = 1(x - 2)
y - 7 = x - 2
y = x - 2 + 7
y = x + 5 <-- your equation

Answer 6

x − y = −1

x − y = −2

x − y = − 5

x − y = − 6
these are the answer chocies

Answer 7

@kelliegirl33 would it be the last one?

Answer 8

y = x + 5
x - y = -5

Answer 9

0ok one more

Select the equations that are parallel and perpendicular to y = one over fourx + 7 and that pass through the point (−8, 9).

parallel: y = one over fourx − 11
perpendicular: y = −4x + 23

parallel: y = −4x + 11
perpendicular: y = one over fourx − 4

parallel: y = 4x − 7
perpendicular: y = negative one over fourx − 7

parallel: y = one over fourx + 11
perpendicular: y = −4x − 23

Answer 10

I am sorry but I got to go now......I do not have time to do this...sorry

Answer 11

please! I have to! this is my final exam and this is the last question and then I can submit it. PLEAEE

Answer 12

@kelliegirl33

Answer 13

I'm here. I'll help. In the future, start a new post for each question.

Answer 14

ok I just did! please help