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Precalculus 25 Online
OpenStudy (karinamtz0213):

Help pleaseee! The problem is located in the comment below :) Thanks.

OpenStudy (karinamtz0213):

OpenStudy (mathstudent55):

For non-negative a and b, \( \sqrt{a^2b^4} = ab^2 \) Now square the first expression and raise the second expression to the 4th power and multiply them together to find what ab^2 is equal to.

OpenStudy (karinamtz0213):

i dont how to solve it

OpenStudy (mathstudent55):

We need to find a and b^2, and then multiply them together. \( \sqrt{a} = c\sqrt{d} \) Square both sides: \(a = c^2d\) We have a. \( \sqrt{b} = c\sqrt{d} \) Raise both sides to the 4th power to find b^2: \( (\sqrt{b})^4 = (c\sqrt{d})^4 \) \( b^2 = c^4d^2 \) Now we have b^2. Now we multiply a by b^2: \(c^2d \times c^4d^2 \) \(c^6d^3 \)

OpenStudy (mathstudent55):

None of the choices are correct.

OpenStudy (anonymous):

not this again!!

OpenStudy (anonymous):

we went around and around with this for the past few days none of the possible answers given are correct don't waste time trying to figure out which incorrect answer is best !

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