Question

can you please help me with this problem

Answer 1

sure. if i can

Answer 2

can you do it

Answer 3

ahh. midterm exams xD

Answer 4

oo, pang 1st batch yan

Answer 5

try ko po

Answer 6

salamat

Answer 7

help me please

Answer 8

dere? is the straight line vertical which dividing angle 30 and 50 ?

Answer 9

yeah it is

Answer 10

what happen?

Answer 11

nasagutan mo

Answer 12

what is the question?

Answer 13

i have it attach

Answer 14

ok, free body diagrams:

Newton's second laws:
The objects are in equilibrium so net force in all directions must be zero. I can decompose the forces in two directions: horizontal and vertical:
Let's first take object at left side:
horizontal components:
\[Fcos \theta -N_1\sin 50^0=0\]
verical components:
\[Fsin \theta +N_1\cos 50^0-P=0\]
another object:
horizontal components:
\[Fcos \theta -N_2\sin 30^0=0\]
vertical components:
\[Fsin 30^0 +Q-N_2\cos 30^0=0\]
and if you solve for theta you should get:
\[\tan \theta=\frac{ P \cot 30^0-Qcot 50^0 }{ P+Q } \rightarrow \theta=10,72^0\]
F is the force that object A acts on object B and vice versa (Newton's third law)