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Mathematics 23 Online
OpenStudy (anonymous):

medal for best :) solve using the fundamental theorem of algebra: v=x^3+11x+28

OpenStudy (anonymous):

I really just need help getting started....

OpenStudy (anonymous):

it is cubic, so it is going to be a problem you might could guess and check for this guess only negative numbers that divide 28

OpenStudy (anonymous):

but what am I guessing?

OpenStudy (anonymous):

i am not sure who wrote this problem, but you do not "solve" anything using the fundamental theorem of algebra

OpenStudy (anonymous):

i mean, am i factoring this or...?

OpenStudy (anonymous):

"solve" in this case means find the zeros

OpenStudy (anonymous):

okay, "find the solutions"?

OpenStudy (anonymous):

\[x^3+11x+28 =0\]

OpenStudy (anonymous):

so am i factoring?

OpenStudy (anonymous):

you can't factor this one using integers there is not typo in this question, right?

OpenStudy (uri):

I think it should be x^2

OpenStudy (anonymous):

no typo, but i can factor it into (x^2+4x)(x+7), right?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

oops. i didn't have a typo, i just created the problem wrong... im in the middle of a project and this is what i got as a result of my last part.... should be x^3 +11x^2+28

OpenStudy (anonymous):

*28x

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

\[ x^3 +11x^2+28x=0\] we can do

OpenStudy (anonymous):

today is just not my day, im sorry anyway, NOW can i factor into (x^2+4x)(x+7)?

OpenStudy (anonymous):

each term has a common factor of \(x\)

OpenStudy (anonymous):

\[x(x^2+11x+28)\] is the first step

OpenStudy (anonymous):

okay

OpenStudy (uri):

Then find a number when adding is 11 and multiplying is 28

OpenStudy (anonymous):

7 and 4?

OpenStudy (anonymous):

now maybe you can factor \(x^2+11x+28\) i can't because i suck at factoring, do what @uri says and tell your math teacher one does not "solve" anything with the fundamental theorem of algebra!

OpenStudy (anonymous):

ill be sure to pass along the message, thanks :)

OpenStudy (uri):

Ya so x^2+11x+28 x^2+7x+4x+28 Find common now

OpenStudy (anonymous):

so... @uri would my next step be x(x+4)(x+7)?

OpenStudy (uri):

x(x+7)+4(x+7)

OpenStudy (anonymous):

okay, not following but ill play along

OpenStudy (uri):

Answer will be x(x+7)(x+4)

OpenStudy (anonymous):

and that's the fundamental theorem of algebra?

OpenStudy (uri):

Well ye

OpenStudy (anonymous):

that is so easy, why they gotta come up with crazy fancy names for everything when they could just say "find the zeros" anyway thanks :)

OpenStudy (uri):

yw!

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