medal for best :) solve using the fundamental theorem of algebra: v=x^3+11x+28
I really just need help getting started....
it is cubic, so it is going to be a problem you might could guess and check for this guess only negative numbers that divide 28
but what am I guessing?
i am not sure who wrote this problem, but you do not "solve" anything using the fundamental theorem of algebra
i mean, am i factoring this or...?
"solve" in this case means find the zeros
okay, "find the solutions"?
\[x^3+11x+28 =0\]
so am i factoring?
you can't factor this one using integers there is not typo in this question, right?
I think it should be x^2
no typo, but i can factor it into (x^2+4x)(x+7), right?
no
oops. i didn't have a typo, i just created the problem wrong... im in the middle of a project and this is what i got as a result of my last part.... should be x^3 +11x^2+28
*28x
lol
\[ x^3 +11x^2+28x=0\] we can do
today is just not my day, im sorry anyway, NOW can i factor into (x^2+4x)(x+7)?
each term has a common factor of \(x\)
\[x(x^2+11x+28)\] is the first step
okay
Then find a number when adding is 11 and multiplying is 28
7 and 4?
now maybe you can factor \(x^2+11x+28\) i can't because i suck at factoring, do what @uri says and tell your math teacher one does not "solve" anything with the fundamental theorem of algebra!
ill be sure to pass along the message, thanks :)
Ya so x^2+11x+28 x^2+7x+4x+28 Find common now
so... @uri would my next step be x(x+4)(x+7)?
x(x+7)+4(x+7)
okay, not following but ill play along
Answer will be x(x+7)(x+4)
and that's the fundamental theorem of algebra?
Well ye
that is so easy, why they gotta come up with crazy fancy names for everything when they could just say "find the zeros" anyway thanks :)
yw!
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