Mathematics
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OpenStudy (anonymous):
Help..Integration and Differentiation
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OpenStudy (anonymous):
These are two separate questions!!
OpenStudy (anonymous):
sin y = x sin(a+y)
siny / sin(a+y) = x
now try to differentiate
OpenStudy (anonymous):
*Using quotient rule
OpenStudy (anonymous):
Can ya help me thru the steps!!
OpenStudy (anonymous):
@Yahoo!
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OpenStudy (anonymous):
@surjithayer
OpenStudy (anonymous):
@uri
OpenStudy (anonymous):
@ilfy214
OpenStudy (anonymous):
@Loser66 @litchlani @Hero
OpenStudy (anonymous):
@amistre64
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OpenStudy (anonymous):
@Fifciol
OpenStudy (anonymous):
@cambrige Try to Solve it with the Hint
OpenStudy (anonymous):
@Yahoo! Dont u think I wud hav if I understood the hint...-_-
OpenStudy (anonymous):
Is this correct?? @Yahoo!
OpenStudy (anonymous):
If yes.Pls help on the next question posted in the same attachment!!
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OpenStudy (anonymous):
\[x=\frac{ \sin y }{ \sin \left( a+y \right) }=\frac{ \sin \left\{ \left( a+y \right)-a \right\} }{ \sin \left( a+y \right) }\]
\[or x=\frac{ \sin \left( a+y \right)\cos a-\cos \left( a+y \right)\sin a }{ \sin \left( a+y \right) }\]
\[or x=\cos a-\sin a \cot \left( a+y \right)\]
diff. w.r.t.x,
\[1=0-\sin a \left( -\csc ^{2}(a+y )\right)\frac{ dy }{ dx }\]
\[\frac{ dy }{ dx }=\frac{ 1 }{\sin a \csc ^{2}(a+y) }=\frac{ \sin ^{2}(a+y) }{\sin a }\]
OpenStudy (anonymous):
So mine was r8?? @surjithayer
OpenStudy (anonymous):
Why is cosa derivative 0 @surjithayer ??
OpenStudy (anonymous):
cosa is a constant and its differential is 0
OpenStudy (anonymous):
Oh kay!!
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OpenStudy (anonymous):
yw
OpenStudy (anonymous):
Hey can u give me the idea for the other problems??
OpenStudy (anonymous):
take log of both sides and then differentiate.
OpenStudy (anonymous):
Oh kay..Hold up with me while I give'em a try!!
OpenStudy (anonymous):
And after log we differentiate,I guess??
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OpenStudy (anonymous):
Posting in 1min
OpenStudy (anonymous):
OpenStudy (anonymous):
now substitute the value of y
OpenStudy (anonymous):
x^x???
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
k........last question diff x^y=y^x.....log??
OpenStudy (anonymous):
yes after taking log take all y's on L.H.S and x's on R.H.S
OpenStudy (anonymous):
did a mistake vl post in 2 mins
OpenStudy (anonymous):
Correct??
OpenStudy (anonymous):
@surjithayer
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OpenStudy (anonymous):
@Loser66 ...is it r8??
OpenStudy (anonymous):
absolutely correct.
OpenStudy (anonymous):
Ta man..Life saver u r!!