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Mathematics 19 Online
OpenStudy (anonymous):

Help..Integration and Differentiation

OpenStudy (anonymous):

These are two separate questions!!

OpenStudy (anonymous):

sin y = x sin(a+y) siny / sin(a+y) = x now try to differentiate

OpenStudy (anonymous):

*Using quotient rule

OpenStudy (anonymous):

Can ya help me thru the steps!!

OpenStudy (anonymous):

@Yahoo!

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

@uri

OpenStudy (anonymous):

@ilfy214

OpenStudy (anonymous):

@Loser66 @litchlani @Hero

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@Fifciol

OpenStudy (anonymous):

@cambrige Try to Solve it with the Hint

OpenStudy (anonymous):

@Yahoo! Dont u think I wud hav if I understood the hint...-_-

OpenStudy (anonymous):

Is this correct?? @Yahoo!

OpenStudy (anonymous):

If yes.Pls help on the next question posted in the same attachment!!

OpenStudy (anonymous):

\[x=\frac{ \sin y }{ \sin \left( a+y \right) }=\frac{ \sin \left\{ \left( a+y \right)-a \right\} }{ \sin \left( a+y \right) }\] \[or x=\frac{ \sin \left( a+y \right)\cos a-\cos \left( a+y \right)\sin a }{ \sin \left( a+y \right) }\] \[or x=\cos a-\sin a \cot \left( a+y \right)\] diff. w.r.t.x, \[1=0-\sin a \left( -\csc ^{2}(a+y )\right)\frac{ dy }{ dx }\] \[\frac{ dy }{ dx }=\frac{ 1 }{\sin a \csc ^{2}(a+y) }=\frac{ \sin ^{2}(a+y) }{\sin a }\]

OpenStudy (anonymous):

So mine was r8?? @surjithayer

OpenStudy (anonymous):

Why is cosa derivative 0 @surjithayer ??

OpenStudy (anonymous):

cosa is a constant and its differential is 0

OpenStudy (anonymous):

Oh kay!!

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

Hey can u give me the idea for the other problems??

OpenStudy (anonymous):

take log of both sides and then differentiate.

OpenStudy (anonymous):

Oh kay..Hold up with me while I give'em a try!!

OpenStudy (anonymous):

And after log we differentiate,I guess??

OpenStudy (anonymous):

Posting in 1min

OpenStudy (anonymous):

OpenStudy (anonymous):

now substitute the value of y

OpenStudy (anonymous):

x^x???

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

k........last question diff x^y=y^x.....log??

OpenStudy (anonymous):

yes after taking log take all y's on L.H.S and x's on R.H.S

OpenStudy (anonymous):

did a mistake vl post in 2 mins

OpenStudy (anonymous):

Correct??

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

@Loser66 ...is it r8??

OpenStudy (anonymous):

absolutely correct.

OpenStudy (anonymous):

Ta man..Life saver u r!!

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