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@BangkokGarrett @ilfy214 @CGGURUMANJUNATH
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G(x) = x^3 - x^2 Remember, if we want to shift right a units, look at G(x-a) G(x-3) =(x-3)^3 - (x-3)^2 I'd just leave your answer like\[G(x-3)=(x-3)^{3}-(x-3)^{2}\]
oops 2 units! Change all my 3s to 2s. sorry!
but not the exponnts. the first exponent remains 3 and the second exponent remains 2
Exactly! \[F(x) = (x - 2)^{3} - (x - 2)^{2}\]
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yes.. and use F(x) like ilfy...not G(x-3) in your final answer
I think she got the picture @BangkokGarrett lolz
@mayafrancis Do you get it maya?
yes :)
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