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Chemistry 22 Online
OpenStudy (anonymous):

Calculate the pOH [H3O+] = 1.25 x 10^-11 M

OpenStudy (kainui):

So you have the opposite of what you need, do you know the relationship between pH and pOH or the relation between [H3O+] and [OH-]?

OpenStudy (kainui):

Remember that for every H2O that dissociates you must have 1 H+ (that can attach to another H2O to be H3O+ basically) and one OH-. So you have this conservation of mass going on.

OpenStudy (anonymous):

@Kainui my answer was 2.1 when I plugged it into the calculator, what am I doing wrong?

OpenStudy (kainui):

What did you plug into your calculator?

OpenStudy (anonymous):

1.25*10^-11

OpenStudy (anonymous):

actually I don't remember

OpenStudy (anonymous):

what should my answer have been? cuz I thin 2.1 is close but I don't remember how I got it, I am reviewing from a little while ago

OpenStudy (kainui):

pH and pOH are numbers between 0 and 14 normally.

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