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Mathematics 17 Online
OpenStudy (anonymous):

In triangle ABC, AB=5cm, BC=3cm and AC=7cm. Find the measure of angle opposite to largest side

OpenStudy (zzr0ck3r):

|dw:1376118753324:dw| law of cosines \[a^2+b^2-2ab*cos(x) = c^2\] where a,b are the legs connected to x so 5^2+3^-2*5*3cos(x) = 49

OpenStudy (campbell_st):

so you need to use the cosine rule... but hey... why learn when people just give answers

OpenStudy (zzr0ck3r):

did I give an answer?

OpenStudy (campbell_st):

if you have microsoft math... just go an use the triangle solver

OpenStudy (zzr0ck3r):

in pretty sure this is exactly what you did on the last question @campbell_st I can show you if you forgot

OpenStudy (campbell_st):

great... email me the link..lol...

OpenStudy (zzr0ck3r):

anyway @Varu do you get whats going on so far?

OpenStudy (anonymous):

yup

OpenStudy (campbell_st):

but at least it contained an explanation... which aids learning... |dw:1376119145921:dw|

OpenStudy (zzr0ck3r):

I was getting to that until I was interrupted....

OpenStudy (zzr0ck3r):

I explained just as much as you...

OpenStudy (anonymous):

then what is the answer ?

OpenStudy (anonymous):

is the answer sq. root of 49

OpenStudy (zzr0ck3r):

@campbell_st since you like to point out that I am not using correct terminology can you please finish what you started? we all know you are the MATH so why should anyone else help. god forbid they say the angle that has the lines connected to it so that the user will understand .....

OpenStudy (anonymous):

I have an answer For me the answer is 60 degree

OpenStudy (anonymous):

Law of Cosine Cos(B)= a^2+c^2-b^2/-2ac

OpenStudy (zzr0ck3r):

make sure you check with @campbell_st before you say anything

OpenStudy (campbell_st):

why me... I'm in 8th grade... not university

OpenStudy (anonymous):

I don't like it when I see people telling others how they're giving answers. I mean sure it's not the greatest of things to do and when someone does so then one can PM the person and tell them that they shouldn't reveal answers. However, this should only be the case when the person does indeed reveal answers immediately however this wasn't the case here. @zzr0ck3r only showed the approach to solve the question so the OP can do the question him/herself..

OpenStudy (zzr0ck3r):

the op told me in private I used the wrong terminology, then told me I must be in 8th grade for explaining it like that...the op @campbell_st is a fluttering retriceole

OpenStudy (anonymous):

lol

OpenStudy (campbell_st):

I still don't know what fluttering retriceole is... even after googling it

OpenStudy (zzr0ck3r):

yep

OpenStudy (anonymous):

@campbell_st Study Oblique Triangles .

OpenStudy (campbell_st):

ok... well maybe we'll study them next year

OpenStudy (anonymous):

guys chill

OpenStudy (campbell_st):

lol.. this is just to funny... how old are you zz I'm 14...

OpenStudy (anonymous):

WEre the same Im 14 too But I already know that Topic

OpenStudy (campbell_st):

ok....I'll not comment

OpenStudy (anonymous):

Because the best thing in doing math Is to study it by yourself

OpenStudy (campbell_st):

but I do need to know what a fluttering retriceole is... the only google reference is open study

OpenStudy (campbell_st):

ok... thanks for being such a polite person and telling me good luck with your studies

OpenStudy (anonymous):

|dw:1376120608661:dw|\[Cos (B) = a ^{2} + c ^{2} - b ^{2}\div-2ac\]

OpenStudy (anonymous):

formula for getting the Angle B

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