Question

can anybody please help me with this?

Answer 1

all you need to do is substitute and evaluate

Answer 2

did you replace x with 2-root3

Answer 3

you will get it

Answer 4

you will have a squaring the binomial will be the hardest part

Answer 5

there will be a hardest part cos sum and difference of two binomial has a Shortcut

Answer 6

answer is the first option

Answer 7

it is simple replacing x

Answer 8

\[(2-\sqrt{3}) ^{2} \]
Just square only 1st and second term

Answer 9

if your first answer is not in the choices just rationalized it when a Square root is in the denominator

Answer 10

How do I substitute in the beginning? can somebody please explain because I don't understand it at all :(

Answer 11

the ans to \[(2-\sqrt{3})^2\] is \[4+3-4\sqrt{3}\]

Answer 12

just substitute 2 - sqr.root of 3 to x

Answer 13

Wrong @Varu 4-3 is the answer in (2-sqr.root of 3)

Answer 14

no @EinsteinMorse \[(a-b)^2=a^2+b^2-2ab\]

Answer 15

\[f(x) = (2-\sqrt{3}) ^{2}/ 2-\sqrt{3} -2\]

Answer 16

OK I substituted. I Understand that part. What comes next?

Answer 17

cancel the 2 in the denominator

Answer 18

why cancel the -2 ? :(

Answer 19

2-2=0

Answer 20

you have to cancel 2 and -2

Answer 21

to cancel it with the 2 in the numerator ?

Answer 22

no

Answer 23

why

Answer 24

with what does it get canceled?

Answer 25

\[2-\sqrt{3}-2= -\sqrt{3}\]

Answer 26

@RH do you understand

Answer 27

2-2=0

Answer 28

so only \[-\sqrt{3}\]

Answer 29

yah so the answer in the denominator is -sqr.root 3

Answer 30

OOOo YES I DO! sorry

Answer 31

what comes next?

Answer 32

in the numerator

Answer 33

yes, -sqrt of 3

Answer 34

4+3- 2*2* sq root3

Answer 35

from \[(a-b)^2\]

Answer 36

it becomes 7-4 sq root3

Answer 37

sorry your correct :) Im confused only

Answer 38

happens

Answer 39

yes I understand this too...thanks

Answer 40

is there more?

Answer 41

so now \[7-4\sqrt{3}/-\sqrt{3}*\sqrt{3}/\sqrt{3}\]

Answer 42

\[7-4\sqrt{3} / -\sqrt{3}\]

then Rationalized it

Answer 43

so answer is \[7\sqrt{3}-12/-3\]

Answer 44

nice correct that is the answer @RH
we got the same answer

Answer 45

So A is the answer? because in the given answers it is +12 and +3 not -3 :(

Answer 46

Yah Coz when Varu rationalized it HE didnt include negative sign so that why he got -12 and -3

Answer 47

@RH Try to rationalized it again then include the negative sign and you will get +12 and + 3 for denominator

Answer 48

But the Answer is letter A

Answer 49

Ok, thanks a lot for everything! :)

Answer 50

I tell you something When you got a Sqr root sign in the denominator just copy the denominator then multiply it to ur first fraction

Answer 51

Welcome

Answer 52

ok! Thanks for the advice :)