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Algebra
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The vertex is (0,3) and point (2,5) lies on graph.
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what are you trying to find?
the equation of the line
hehe jst borrowed ds account from my frnd :)
in y=mx + B format?
yes..
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so to find slope, you want to do y2-y1/x2-x1 since your point is the 2nd point, its (x2, y2) slope is 5-3/2-0=1
also, for point b, use the y intercept for your vertex
your equation looks like y=x+1
the slope is 1
yea
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isnt it?
yes it is. and in the equation y=mx + b, m is where you put the slope
ok...got it
and i will use (y2-y1) = m(x2-x1) ... ???
no.
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it's a parabola?!
(y2-y1)/(x2-x1)
no its a simple equation If you want, try graphing it out and do rise over run
|dw:1376134648702:dw| Graph would look something like this
but theres a vertex.. hehe
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