Mathematics
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OpenStudy (anonymous):
x = t^2 + 3
y = 2t
Eliminate the parameter and write a rectangular equation
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OpenStudy (anonymous):
substitute
OpenStudy (anonymous):
substitute what?
OpenStudy (anonymous):
t = y/2
OpenStudy (anonymous):
(y/2)^2 + 3 ?
OpenStudy (anonymous):
x = that
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OpenStudy (anonymous):
thats what the answer is ?
OpenStudy (anonymous):
you tell me... do you know the definition of rectangular equation? If not, look it up to be sure
OpenStudy (anonymous):
so yes , thats the answer..
OpenStudy (anonymous):
OpenStudy (anonymous):
what?
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OpenStudy (anonymous):
(y/2)^2 + 3 is that the answer, or no ?
OpenStudy (anonymous):
i'm too lazy to say... you're too lazy to look
OpenStudy (anonymous):
but i know the answer and you need it
OpenStudy (anonymous):
and all you have to do is look at what i sent
OpenStudy (anonymous):
so you don't need me any more just get off your butt and do something
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OpenStudy (anonymous):
if you don't want to help just don't reply. its that easy. dont need to be mean about it.
OpenStudy (anonymous):
i'm not, but you're not asking for help... just answers
OpenStudy (anonymous):
di you look at what i sent?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
what part is confounding you?
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OpenStudy (anonymous):
all of it
OpenStudy (anonymous):
what is a parametric equation?
OpenStudy (anonymous):
just help me understand , i replaced the t with 2/y
OpenStudy (anonymous):
basically the question i gave you
OpenStudy (anonymous):
did you see them do the same in the attachement? did you look at page 2, ex. 2?
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OpenStudy (anonymous):
so the answer is 3+y^2/2
OpenStudy (anonymous):
no... t = y/2. so t^2 = (y/2)^2
not t = y^2/2
they're different
OpenStudy (anonymous):
so its 3 + (y/2) ^2
OpenStudy (anonymous):
or 3 + y^2 / 4