Write the expression as either the sine, cosine, or tangent of a single angle. sin ( pi / 2 ) * cos( pi / 7 ) + cos ( pi / 2 ) * sin (pi/ 7)
This is the result of a sum of sines formula. This is what you get when you have sin(a + b). So just take what you have and put it backwards into the sum of sines sin(a + b)
So add pi over 2 and pi over 7 together
Pretty much xD
Alright but first would I cross multiply them
Nope, it's just \[\sin(\frac{ \pi }{ 2 }+\frac{ \pi }{ 7 })\]
Ok so it would be \[\sin ( \frac{ \pi }{ 9 } )\]
Well, we need to add the fractions like normal, common denominators and things like that.
Alright would it be \[\sin ( 2 \pi / 9 ) \] then
Hmm \[\frac{ \pi }{ 2 }*\frac{ 7 }{ 7 } + \frac{ \pi }{ 7 }*\frac{ 2 }{ 2 }\] \[\frac{ 7\pi }{ 14 }+ \frac{ 2\pi }{ 14 } = \frac{ 9\pi }{ 14 }\] Kinda see how?
yeah and this would be a sin expression
Yeah, itd be sin(9pi/14) and that would be your answer.
Ok thanks
Mhm.
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