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Chemistry 24 Online
OpenStudy (anonymous):

I'll fan you and give you a medal please help me Describe, in detail, how to make 2.0 liters of a 1.0 molar HCl solution from a 12.5 molar HCl stock solution

OpenStudy (anonymous):

@cwrw238 @Compassionate please help me

OpenStudy (anonymous):

@dan815 @Loser66 what do you guys think

OpenStudy (loser66):

oops, I forgot all of them, sorry, friend

OpenStudy (anonymous):

its okay I'll fan you anyway cause thats what sheerios do

OpenStudy (anonymous):

@abb0t help me?

OpenStudy (abb0t):

\(M_1V_1=M_2V_2\)!!

OpenStudy (anonymous):

what does that mean?

OpenStudy (abb0t):

Use the given equation to solve for \(V_1\)

OpenStudy (anonymous):

there is no v1 in the question

OpenStudy (abb0t):

That is why you're solving for it!

OpenStudy (anonymous):

what are you talking about

OpenStudy (anonymous):

this is my question Describe, in detail, how to make 2.0 liters of a 1.0 molar HCl solution from a 12.5 molar HCl stock solution theres no m or v here and yes I'm serious

OpenStudy (abb0t):

M = molars (M) V = volume (L)

OpenStudy (abb0t):

in order to know how to make 2.0 liters, you need to know how much you started with!

OpenStudy (anonymous):

ok so what now

OpenStudy (abb0t):

Now, plug in the given information! You already have \(M_1\), \(M_2\), and \(V_2\). But you don't know how much \(V_1\) you have. \(V_1\) is your initial volume! So, like from algebra, rearrange the formula to solve. Once you rearrange your formula using basic algebra tricks, plug in the given values! That will basically tell you the volume you need to add to the solution to get \(V_2\) at the molars given.

OpenStudy (anonymous):

that was no help at all

OpenStudy (abb0t):

I'm not doing the work for you. I already told you what to do. Best of luck with your question.

OpenStudy (abb0t):

Once you get the answer, I can check if you're correct. If you are not correct, I can further assist you, but I don't see you putting any effort here.

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