Help me find the y determinant!
Choose the value of the y determinant (Dy) in the following system. 2x - y = 7 3x + 4y = 5
Do you know how to find the determinate period?
Swap out the y coefficients with the answer column
So just find the determinate of this matrix:\[ \begin{bmatrix} 2 & 7 \\ 3 & 5 \end{bmatrix} \]
how?
\(\left[ \begin{matrix} 2&-1&| &\color{red}{ 7}\\ 3& 4& | & \color{red}{5} \end{matrix} \right]\implies D_y = \left[ \begin{matrix} 2&\color{red}{7}\\ 3& \color{red}{5} \end{matrix} \right] \)
You must know how to find a determinant by now...
oh ok..so what is the final answer?
I forgot how to sorry
agree on that with @wio
well, if you forgot, it's about time to open up the book and recheck the material
I'm pretty sure it's there
how do I find the answer?
by rereading the chapter on finding the determinants
http://www.math.dartmouth.edu/archive/m8s00/public_html/handouts/matrices3/node7.html
-11
yes
got it..now do I find the x determinant of this one? 4x - y = 5 3x + 2y = 7
can you help me set it up?
\( \left[ \begin{matrix} 4&-1&| &\color{red}{ 5}\\ 3& 2& | & \color{red}{7} \end{matrix} \right]\implies D_x = \left[ \begin{matrix} \color{red}{\square?}&-1\\ \color{red}{\square?}& 2 \end{matrix} \right] \)
5 and 7?
yes
can you help me with one more?
None of the choices seem right to me
|dw:1376169630993:dw| which means that 80 = 2 * 2 * 2 * 2 * 5 = \(\bf 2^4 \times 5\) \(\bf \Large 2\sqrt[4]{80} \implies 2\sqrt[4]{2^4\times5}\)
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