Question

what are the coordinates of the vertices of (x-2)^2/ 36+(y+1)^2/25=1

Answer 1

Alright, so this is an ellipse. Now in an ellipse, a^2 is always going to be the largest of the two denominators. When a^2 is underneatht he x^2 term, we have an ellipse that is flattened along the x-axis. Since 36 is the higher of the two denominators and is under x^2, we know we will flatten along the x-axis and our verticies will be found to the left and the right of our center. So now our center appears to be at (2,1) due to the shifts. Finally, the verticies are +/- a units from the center. Since a^2 would be 36, then a is 6. So from the center, one vertex would be 6 units right of the center and the other would be 6 units left of the center. Make sense?

Answer 2

isnt center at (2,-1)

Answer 3

Yes it is, I apologize.

Answer 4

so the coordinates are (0,6) and (0,-6)

Answer 5

do u have to use the equation a^2+b^2=c^2

Answer 6

Well remember, we are 6 units from the center of the ellipse, not from the origin. Not only that, but since the ellipse is flattened along the x-axis, the verticies have to be left and right 6 units.



And no, you only use that equation for foci.