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Mathematics 18 Online
OpenStudy (anonymous):

Which point lies in the solution set for the following system of inequalities? y < 2x + 4 y < -2x + 2 (1, 0) (-5, -2) (0, -3) (-1, 5)

OpenStudy (anonymous):

please help me

OpenStudy (anonymous):

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OpenStudy (anonymous):

the easiest way is to plug the values of the given points.

OpenStudy (anonymous):

for example, plug (1, 0) : the first one gives 0 < 2 +4 so 0 < 6 this is true the second one gives: 0 < -2 + 2 so 0 < 0 this is false so this point is not the answer.

OpenStudy (anonymous):

so which is the asnwer

OpenStudy (anonymous):

now try and plug the other points and see

OpenStudy (anonymous):

i still didnt get the answer

OpenStudy (anonymous):

show me how you plug the second point for example

OpenStudy (anonymous):

no i mean i dont understand

OpenStudy (anonymous):

so again, for the first point (1,0) this point means x=1 and y=0 now you have two inequalities to satisfy A. y < 2x + 4 B. y < -2x + 2 if you substitute x =1 and y = 0 in A you get 0 < 2*1 + 4 0 < 6 this is true. but, if you subtitute x =1 and y = 0 in B you get 0 < -2 + 2 0 < 0 this is false. so this point doesnt satisfy both inequalities.

OpenStudy (anonymous):

still dont get it

OpenStudy (anonymous):

you dont even try :(

OpenStudy (anonymous):

show me how you do it with the second point

OpenStudy (anonymous):

another way to solve this problem is by graphing both inequalities.

OpenStudy (anonymous):

i graphed it

OpenStudy (anonymous):

good. now which of the points is in the dark area ?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

(0,-3)

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