In polar-cylindrical coordinates, what is horizontal velocity?
Hello! If you're using polar as like...
\(x\) is horizontal and \(y\) is vertical...
in polar u use, r, theta
And instead you're using \(r\) and \(\theta\)...|dw:1376244337612:dw|
@Mashy :)
So, @gorica , what do you have to do to find the horizontal part? Any ideas? It'll be good practice to try to think about this, but I'm sure @Mashy and I can help you get there if you're not sure!
well m sure u alone can handle it :P.. so m out :D
I have position vector \[\vec r=r \vec {e_r}+z \vec {e_z}\] and I have velocity vector \[\dot {\vec r}=\dot r \vec {e_r}+r \dot \theta \vec {e_\theta}+\dot z \vec {e_z}\]
Oh, gosh, more complicated than I thought. @Mashy , please check this out when you come back on!
I messaged a person who might be able to understand that.
|dw:1376245533310:dw|
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