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Physics 19 Online
OpenStudy (gorica):

In polar-cylindrical coordinates, what is horizontal velocity?

OpenStudy (theeric):

Hello! If you're using polar as like...

OpenStudy (theeric):

\(x\) is horizontal and \(y\) is vertical...

OpenStudy (anonymous):

in polar u use, r, theta

OpenStudy (theeric):

And instead you're using \(r\) and \(\theta\)...|dw:1376244337612:dw|

OpenStudy (theeric):

@Mashy :)

OpenStudy (theeric):

So, @gorica , what do you have to do to find the horizontal part? Any ideas? It'll be good practice to try to think about this, but I'm sure @Mashy and I can help you get there if you're not sure!

OpenStudy (anonymous):

well m sure u alone can handle it :P.. so m out :D

OpenStudy (gorica):

I have position vector \[\vec r=r \vec {e_r}+z \vec {e_z}\] and I have velocity vector \[\dot {\vec r}=\dot r \vec {e_r}+r \dot \theta \vec {e_\theta}+\dot z \vec {e_z}\]

OpenStudy (theeric):

Oh, gosh, more complicated than I thought. @Mashy , please check this out when you come back on!

OpenStudy (theeric):

I messaged a person who might be able to understand that.

OpenStudy (gorica):

|dw:1376245533310:dw|

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