Question

@pgpilot326 @ash2326 @satellite73

Answer 1

do you recognize this as a shift (both horizontal and vertical)?

Answer 2

f(x) = x^3 is the parent function

Answer 3

yes

Answer 4

so what are the shifts?

Answer 5

wait im confused

Answer 6

ok, what is confusing you?

Answer 7

look at how the point (0, 0) moves... that will give you your shifts.

Answer 8

it shifts to the left right

Answer 9

and...

Answer 10

2 units to the left?

Answer 11

not the zero... look at the graph.
(0, 0) moves 1 unit left and 4 units up.

Answer 12

but i see 2 though?

Answer 13

how would we write the equation

Answer 14

do you see the (-1,4) point? it's like th e(0, 0) ponit moved up there and the rest of the graph with it.

to do a horizontal shift, we transform the parent graph, f(x), by plugging in x-h for x.

so g(x) = f(x-h) where h is the horizontal shift and x=h => x-h =0.

you;re new vertex is at (-1, 4) so the x value is -1. what does h have to be so that -1+h=h?

Answer 15

to do aa vertical shift, we simply add to the y (or f(x)).

so g(x) = f(x) + k is a shift of k units. if k>0 then its a shift up and if k<0 then its a shift down.

we combine the two shifts to get the total movement.

Answer 16

im so confused? whats k?