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Mathematics 25 Online
OpenStudy (anonymous):

mathcalculus HELP: Determine the values of where the tangent line is horizontal for the function:

OpenStudy (anonymous):

OpenStudy (anonymous):

i know i have to find the derivative and set it to zero but it's not coming out to be correct. can anyone help me

OpenStudy (anonymous):

so i did 3x^2-6x-4=0

OpenStudy (anonymous):

i tried to use the quadratic formula and got sqrt(21)+3/3

OpenStudy (anonymous):

+ or - sqrt(21)+3/3

OpenStudy (anonymous):

also aka 2.52753...

OpenStudy (dumbcow):

derivative seems correct

OpenStudy (anonymous):

to find what x = to... ?

OpenStudy (anonymous):

i used quadratic formula

OpenStudy (anonymous):

@dumbcow dont i have to do that to find x??

OpenStudy (anonymous):

im getting it wrong,

OpenStudy (dumbcow):

yes everything looks correct to me...do they want exact or decimal answer?

OpenStudy (anonymous):

can i use quadratic formula for ths one?

OpenStudy (anonymous):

@dumbcow

OpenStudy (anonymous):

??

OpenStudy (anonymous):

????????????????????????

OpenStudy (dumbcow):

yes of course you use quadratic formula...thats how you got your answer that i said looked correct

OpenStudy (anonymous):

im not getting that using quadratic formula

OpenStudy (anonymous):

im getting something totally different and wrong

OpenStudy (dumbcow):

\[x = \frac{3 \pm \sqrt{21}}{3}\]

OpenStudy (anonymous):

yes! but from 6+2*sqrt(21)/6?

OpenStudy (anonymous):

shouldnt it be 1+ or - sqrt 21/3

OpenStudy (dumbcow):

same thing, just a matter of splitting up fraction or keeping it as single fraction

OpenStudy (anonymous):

no it's not because the answer is 1+ sqrt (7/3) gives me 2.52753 and 1+sqrt 21/3 gives me 1.86086!

OpenStudy (anonymous):

@dumbcow

OpenStudy (dumbcow):

hmm \[\frac{\sqrt{7}}{\sqrt{3}} = \frac{\sqrt{21}}{3} \]

OpenStudy (anonymous):

hmmm?

OpenStudy (anonymous):

@dumbcow

OpenStudy (anonymous):

try it on a calculator.

OpenStudy (dumbcow):

oh you added the "1" before dividing by "3"

OpenStudy (anonymous):

okay from my answer.... not the internet.. 6+2 sort(21)/3.... where do i go from there?

OpenStudy (dumbcow):

well it should be a 6 on bottom

OpenStudy (anonymous):

no i didn't add anything.

OpenStudy (anonymous):

okay sure a 6. i thought it could be a 3 to narrow it down

OpenStudy (anonymous):

so 6+or-2sqrt(21)/6

OpenStudy (dumbcow):

i dont see the problem, you posted answer in beginning... " i tried to use the quadratic formula and got sqrt(21)+3/3 "

OpenStudy (anonymous):

so it is a 3 in the denominator!

OpenStudy (dumbcow):

\[\frac{6 \pm 2\sqrt{21}}{6} = \frac{2(3 \pm \sqrt{21})}{6} = \frac{3 \pm \sqrt{21}}{3}\]

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