Expand and simplify (√3+2)^5. Give your answer in the form a+b√3

Question

dumbcow · Answer

use binomial thm:
$$(a+b)^{5} = (5C0) a^{5} + (5C1) a^{4}b+(5C2) a^{3}b^{2}+(5C3)a^{2}b^{3}+(5C4)a b^{4}+(5C5)b^{5}$$

anonymous · Answer

what is $$(5C)?$$

dumbcow · Answer

sorry that is notation for combinations
5 choose 0 = 5!/0!5!

5 choose 3 = 5!/3!2!

dumbcow · Answer

i assumed you have learned about combinations...you can use a calculator to compute them as well

anonymous · Answer

5!/0!5! = 1

dumbcow · Answer

yes

5C0 = 1
5C1 = 5
5C2 = 10
5C3 = 10
5C4 = 5
5C5 = 1

anonymous · Answer

$$(\sqrt{3})^{5}+5(\sqrt{3})^{4}2+10(\sqrt{3})^{3}2^{2}+10(\sqrt{3})^{2}2^{3}+5(\sqrt{3})2^{4}+2^{5}$$

dumbcow · Answer

yep, now hard part....simplify

sqrt3 * sqrt3 = 3

anonymous · Answer

oh god ok

dumbcow · Answer