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Expand and simplify (√3+2)^5. Give your answer in the form a+b√3
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use binomial thm: \[(a+b)^{5} = (5C0) a^{5} + (5C1) a^{4}b+(5C2) a^{3}b^{2}+(5C3)a^{2}b^{3}+(5C4)a b^{4}+(5C5)b^{5}\]
what is \[(5C)?\]
sorry that is notation for combinations 5 choose 0 = 5!/0!5! 5 choose 3 = 5!/3!2!
i assumed you have learned about combinations...you can use a calculator to compute them as well
5!/0!5! = 1
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yes 5C0 = 1 5C1 = 5 5C2 = 10 5C3 = 10 5C4 = 5 5C5 = 1
\[(\sqrt{3})^{5}+5(\sqrt{3})^{4}2+10(\sqrt{3})^{3}2^{2}+10(\sqrt{3})^{2}2^{3}+5(\sqrt{3})2^{4}+2^{5}\]
yep, now hard part....simplify sqrt3 * sqrt3 = 3
oh god ok
to check your answer...i gotta go http://www.wolframalpha.com/input/?i=%28sqrt%283%29%2B2%29%5E5
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