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simplify (2a)-2
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\[(2a)^{-2}\]
You should know that \(\large a^{-1} = \frac{1}{a}\) , so in respect to this idea, we can rewrite \(\large (2a)^{-2}\) as \(\large \frac{1}{(2a)^2}\) Since we've turned the power positive, we can simplify this and get our answer. Are you able to continue on ?
To simplify \(\large \frac{1}{(2a)^2}\) , distribute the power 2 toboth terms inside the parenthesis. \[\large \frac{1}{2^2 \cdot a^2}\] This simplifies to?
@Jhannybean i thought the answer would b 4a
Let's see... \(\large (2a)^{-2} = (2)^{-2} \cdot a^{-2} = \frac{1}{4} a^{-2} = \frac{1}{4a^2} \)
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Same thing as \(\large \frac{1}{2^2\cdot a^2} = \frac{1}{4a^2} \)
Does it make sense? :)
yes it does thanks a lot @Jhannybean
No problemo:)
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