Ask your own question, for FREE!
Mathematics 25 Online
OpenStudy (anonymous):

simplify (2a)-2

OpenStudy (anonymous):

\[(2a)^{-2}\]

OpenStudy (jhannybean):

You should know that \(\large a^{-1} = \frac{1}{a}\) , so in respect to this idea, we can rewrite \(\large (2a)^{-2}\) as \(\large \frac{1}{(2a)^2}\) Since we've turned the power positive, we can simplify this and get our answer. Are you able to continue on ?

OpenStudy (jhannybean):

To simplify \(\large \frac{1}{(2a)^2}\) , distribute the power 2 toboth terms inside the parenthesis. \[\large \frac{1}{2^2 \cdot a^2}\] This simplifies to?

OpenStudy (anonymous):

@Jhannybean i thought the answer would b 4a

OpenStudy (jhannybean):

Let's see... \(\large (2a)^{-2} = (2)^{-2} \cdot a^{-2} = \frac{1}{4} a^{-2} = \frac{1}{4a^2} \)

OpenStudy (jhannybean):

Same thing as \(\large \frac{1}{2^2\cdot a^2} = \frac{1}{4a^2} \)

OpenStudy (jhannybean):

Does it make sense? :)

OpenStudy (anonymous):

yes it does thanks a lot @Jhannybean

OpenStudy (jhannybean):

No problemo:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!