Ask
your own question, for FREE!
Mathematics
5 Online
simplify (2a)-2
Still Need Help?
Join the QuestionCove community and study together with friends!
\[(2a)^{-2}\]
You should know that \(\large a^{-1} = \frac{1}{a}\) , so in respect to this idea, we can rewrite \(\large (2a)^{-2}\) as \(\large \frac{1}{(2a)^2}\) Since we've turned the power positive, we can simplify this and get our answer. Are you able to continue on ?
To simplify \(\large \frac{1}{(2a)^2}\) , distribute the power 2 toboth terms inside the parenthesis. \[\large \frac{1}{2^2 \cdot a^2}\] This simplifies to?
@Jhannybean i thought the answer would b 4a
Let's see... \(\large (2a)^{-2} = (2)^{-2} \cdot a^{-2} = \frac{1}{4} a^{-2} = \frac{1}{4a^2} \)
Still Need Help?
Join the QuestionCove community and study together with friends!
Same thing as \(\large \frac{1}{2^2\cdot a^2} = \frac{1}{4a^2} \)
Does it make sense? :)
yes it does thanks a lot @Jhannybean
No problemo:)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
3 days ago
3 Replies
2 Medals
6 days ago
3 Replies
0 Medals
1 day ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal