Question

PARABOLAS:
Part 1: Write the general form of the equation which matches the graph below.

Part 2: In complete sentences, explain the process taken to find this equation.

Answer 1

So far I know i have to use this standard form x=a(y-3)^2-4

Answer 2

hmm, notice the point A
notice the dashed blue line

what's the distance from the vertex to either one?

Answer 3

4

Answer 4

@jdoe0001

Answer 5

@bahrom7893

Answer 6

so 4, so they're equidistant from the vertex
that means that point A is the focus of the parabola, and the dashed line, x = 4, is the directrix

so for a parabola of that type, the "y" component is the squared thus the "focus form" of it will be \(\bf (y-k)^2=4p(x-h)\)

(h, k) = vertex point of the parabola
p = distance from the vertex to the focus
p < 0, opens to the left
p > 0, opens to the right

Answer 7

notice your (h, k) from the graph is (0, 3) and your P = -4

Answer 8

oh okay ive never seen that formula before