Question

What are the exact solutions of x^2 = 4 − 7x?

Answer 1

I'm not sure but I got \[x=\frac{ 7\pm \sqrt{6} }{ 2 }\]

Answer 2

Help please I will give medals!

Answer 3

Did you use the quadratic formula?

Answer 4

Yes

Answer 5

We usually put all the numbers on the left-hand side before solving by the quadratic formula.
What are the values of a, b, and c that you used?

Answer 6

a=1 b=-7 c=4

Answer 7

To use the quadratic formula, we would need to transpose all the terms to one side first:
\( x^2+7x-4=0 \)
which tells us that, a=? b=? c=?

Answer 8

a=1 b=-7 c=4

Answer 9

The coefficient of x^2 is indeed 1.
What is the coefficient of x and the constant term in the transposed equation?

Answer 10

sorry no offense but what do you mean transposed equation

Answer 11

To use the quadratic formula, we would need to transpose all the terms to one side first:
\( x^2 +7x−4=0 \)

Answer 12

Was my first answer correct ?

Answer 13

Not really.

Answer 14

oh what did i do wrong was the 7 part wrong or 65

Answer 15

The reason i got 7 was because -7 * -1 = 7

Answer 16

49--16=65

Answer 17

You have not used the correct values of b and c in the quadratic formula. The values a=1, b=-7 and c=4 are from different sides of the equation.
You need to transpose ALL the terms to one side before you can determine the values of a, b and c used in the quadratic formula.
In other words, the signs of b and c are not correct, and consequently the solutions are not either.

Answer 18

oh

Answer 19

By the way, your first answer had \( \sqrt{6}\) and not \( \sqrt{65} \).
The latter is closer to the correct solution.

Answer 20

oh sorry

Answer 21

No worries. Back to the question.
What are your values of a, b and c AFTER you have transposed all the terms to the left-hand side?

Answer 22

a=1 b=7 c=-7

Answer 23

*c=-4

Answer 24

Good. Now you are ready to proceed to plug in a, b and c into the quadratic formula and get your solutions!

Answer 25

so the answer is -7 (sqrt)65 over 2

Answer 26

You're almost there, but I think you're still missing something.
Does your quadratic formula read:
\(\huge x = \frac{-b\pm \sqrt{b^2-4ac}}{2a} \)

Answer 27

@arilove1d are you there?

Answer 28

Is the -7 part correct

Answer 29

so instead of 65 its 33

Answer 30

Both the -7 and \( \sqrt{65} \) are correct. You're missing something between them. Check the quadratic formula.

Answer 31

oh the 2

Answer 32

All divided by two is also correct. Just something between -7 and \( \sqrt{65} \) is missing.

Answer 33

\(\huge \pm \)

Answer 34

oh ok thanks !

Answer 35

Theres your medal

Answer 36

ty!