solve e^3x = 5
The definition of natural logarithm is: if \( e^x=a,\) then \( x = log_e a \) Plug in values from your equation and evaluate accordingly.
Ok, so would it be 3x = lne5? and since ln and e are one in the same do they cancel leaving it at 3x = 5?
In mathmate's comment, the e was just a subscript showing the base of the log :) \[\large 3x=\log_e 5 \qquad\to\qquad 3x=\ln 5\]
Oh...ok. Thank you so much. I get it now.
"and since ln and e are one in the same do they cancel leaving it at 3x = 5?" I think there is a mix-up with your concept. \( ln(x) \) is the same as \( log_e(x) \). However, \( log_e(e^x) = x \) does not apply to your case.
Alright. Thank you so it would just be 3x = ln 5?
and consequently solve for x.
Ok so the final result without a calculator woud be x= ln5/3?
Correct,assuming you mean: \( \huge x= \frac{ln(5)}{3} \)
Yes. Thank you so much.
You're welcome! :)
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