Question

help pleaseeee @Psymon @Callisto @seesawn

Answer 1

please i really need help with this

Answer 2

You verify this by plugging in the entire function of g(x) into every x that exists within f(x), then you do it theother way around, plug in the entire function of f(x) into every x that exists within g(x). If they are inverses, then each time you do this susbtitution it should reduce to only x. We get that much so far?

Answer 3

can you show that without words i will understand better

Answer 4

Sure

Answer 5

thanks:)

Answer 6

\[5x + 2 and \frac{ x-2 }{ 5 }\] I'll replace the entire g(x) function into f(x) like this:

\[5(\frac{ x-2 }{ 5 }) + 2\]I took g(x) and put it right insideof the x that f(x) had. Now I simplify.
The 5's on top and bottom cancel out, leaving x - 2 + 2, which is just x. Now that is exactly what we want. Now we need to do this backwards like this:

\[\frac{ (5x+2)-2 }{ 5 }\] I took the entire function of f(x) and plugged it into g(x). Now if I simplify, the 2's on top cancel and then the 5 on top and bottom divides out, leaving only x. Because each time I substituted I was left with only x, these are definitely inverses of each other.

Answer 7

do i flip it or something?

Answer 8

There's nothing to flip. You just plug one function into the other. For example. if I hada function like
f(x) = x^2 - 2x +2 and I asked you tofind f(2), would you know how to do that?

Answer 9

no does x=2?

Answer 10

Alright, wasnt sureif youd understand that or not. But basically if I have
f(x) = 5x + 2 and
g(x) = (x-2)/5



you see what i did?