Question

Bill comments that the weight of his textbooks is only 7 pounds more than ½ the weight of Maria’s textbooks. The total weight of Bill and Maria’s textbooks is 25 pounds. How could this be written as an algebraic expression to determine the weight of Maria’s textbooks?

Answer 1

7+(x*1/2)=25

x stands for the number of pages in Maria's textbook

Answer 2

That is what I thought was the answer but it keeps saying the answer is 3/2 M +7 =25.

Answer 3

Bill's weight of his textbook = 1/2 (maria's textbooks' weight) + 7
maria's textbooks' weight + Bill's weight of his textbook is = 25 pounds

Answer 4

Do substitution from the first equation to the second one

Answer 5

So...1/2M+7=25

Answer 6

This is the same thing as (1/2*M)+7=25

Answer 7

So my answer was right and the answer on the practice test is wrong.

Answer 8

well what is the answer on the practice test?

Answer 9

3/2M +7 =25

Answer 10

@staldk3 Did the question say such thing as 3/2 of the pages at Maria's textbook.

Answer 11

that is the actual answer because (1/2*M)+7 is only bill's textbooks' weight and 25 = both bill's and maria's

Answer 12

Bill comments that the weight of his textbooks is only 7 pounds more than
½ the weight of Maria’s textbooks.
The total weight of Bill and Maria’s textbooks is 25 pounds. How could this be written as an algebraic expression to determine the weight of Maria’s textbooks?

Answer 13

(1/2*M)+7 + M = 25

3/2M + 7 = 25

Answer 14

But iisn't 3/2 stands for 1 1/2

Answer 15

it can be both

Answer 16

Okay then

Answer 17

I don't really understand how you get 3/2.

Answer 18

Me neither

Answer 19

1/2 M + M = ?

Answer 20

But M is just a letter...

Answer 21

its a variable so in this case you would collect like terms

so that it would be (1/2 + 1) M = 3/2 M

Answer 22

So the M =1?

Answer 23

no M does not have a value atm

Answer 24

Then how did you get the 1?

Answer 25

1M is like the same as M

Answer 26

Okay. That makes sense. It was just an imaginary 1.

Answer 27

Thanks!