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A navigator on a ship sights a lighthouse at a bearing of N36°E. After traveling 6.0 miles at a heading of 332°, the ship sights the lighthouse at a bearing of S82°E. How far is the ship from the lighthouse at the second sighting?
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6.1 miles
What is the solution?
|dw:1376306027925:dw|
\[\theta = 360 -332 = 28° \]
C = 82 - 28 =54°
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A = 36 + 28 = 64°
B= 180 - 54 - 64 = 62°
Then use law of sines.
\[\frac{ 8 }{ \sin62 } = \frac{ a }{ \sin64 } \]
oh my mistake. 6/sin 62
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