Find the number of points of discontinuities...HELP please..

Question

dls · Answer

$$\LARGE f(x)=[x^2-2x+2],where~x=[-2,5]$$

dls · Answer

Greatest integer function^ it is

dls · Answer

I think the best method would be graphing it,but I'm confused with how to work it out

terenzreignz · Answer

Not up to your usual standards, @DLS 
This question doesn't seem as sadistic as your usuals... I'm probably missing something XD

terenzreignz · Answer

Just out of interest, what is its vertex? I'd work it out, but it's easier to just ask you :D

terenzreignz · Answer

(1,1) it would seem.

dls · Answer

0,1

dls · Answer

$$X=\frac{-(-2)}{2}=1$$
$$y=0,since~D=b^2-4ac=0$$

dls · Answer

$$y=\frac{4ac-b^2}{4a}=0$$
why the silence
??

ujjwal · Answer

is that floor function?

dls · Answer

yes

terenzreignz · Answer

It probably all boils down to the number of integers between f(-2) and f(5) as you did...

terenzreignz · Answer

Well, if the floor is going to have any discontinuity, it's when the value of the floor-and (lol making up words) is an integer, so just look for the integer values between f(-2) and f(5)

dls · Answer

f(-2)=4+4+2=10
f(5)=25-10+2=17

terenzreignz · Answer

hmm sorry, my bad...

terenzreignz · Answer

uhh
the part where it is decreasing is [-2,1]
The integers between f(-2) to f(1), how many?

dls · Answer

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dls · Answer

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