Question

given kirchhoff's law of R(dQ/dt)+(1/C)Q=E(t), R=5, C=0.05, 60 V
wat is limiting value of charge?is there an equilibrium?

Answer 1

$$R\frac{dQ}{dt}+\frac1CQ=E$$this is a linear equation; consider what happens as \(dQ/dt\to0\) and we taper towards a limiting value:$$\frac1CQ=E\\Q=CE=0.05\times60=3$$

Answer 2

so we ignore R?

Answer 3

I imagine that is the same as the equilibrium value. @freddy_eighty7 only because we let \(dQ/dt\to0\) so \(R\,dQ/dt\to0\) similarly (\(R\) is a constant). logically the resistance won't play a role when there is no current and charge reaches equilibrium