Question

Solve the system by the substitution method.

xy = 12
x2 + y2 = 40

Answer 1

Why can't you do your own work

Answer 2

y dont u pop off

Answer 3

no thanks

Answer 4

yea get off my question if u just wanna start trouble toodels

Answer 5

Thats hilarious sorry! :) But anyways you can use either equation:
\[xy = 12 \]\[x= \frac{ 12 }{ y }\] OR
\[x^2 + y^2 = 40 \]\[x + y = \sqrt{40}\]\[x = \sqrt{40} - y\] **The y and the x can be switched....

Answer 6

All you need to do is plug in.

Answer 7

haha i know .. ok then y does it give me 4 quandrants to pick from ?

Answer 8

example {( 2, 6), ( 6, 2), ( 2, -6), ( 6, -2)}

Answer 9

@ilfy214

Answer 10

From what I solved I got these solutions. 6, 2, -2

Answer 11

im just confused on plugging them in ..

Answer 12

Doesn't it depend on how you solved your equation? Also, when I plugged in -2 and 6 for the first problem, I got -12 instead of 12.

Answer 13

im going w/ b

Answer 14

I was thinking for along the lines of C?

Answer 15

i just dont understand how i allways mess that up

Answer 16

Because in B, if you try using ( 2, -6) and ( -2, 6) you already have a problem for the equation below:\[xy = 12\]\[(2)(-6) = -12\]\[(-2)(6)= -12\]

Answer 17

Its okay! Just choose the options that give you BOTH positive answers

Answer 18

thank u i appreciate it !! :)

Answer 19

You're welcome! :D