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OpenStudy (anonymous):
C?
Factor completely: 2x3 + 10x2 + 14x + 70
(2x2 + 14)(x + 5)
(x2 + 7)(2x + 10)
2(x3 + 5x2 + 7x + 35)
2[(x2 + 7)(x + 5)]
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OpenStudy (anonymous):
Not quite...
OpenStudy (anonymous):
You can still factor it out more
OpenStudy (anonymous):
A?
OpenStudy (anonymous):
The best answer would be B :)
OpenStudy (anonymous):
Use the foil method to multiply it out.
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OpenStudy (anonymous):
A (2x^2+14)(x+5) its by rule
OpenStudy (anonymous):
Now you are just guessing... Go back to C\[2x^3 + 10x^2 + 14x + 70\]\[2 (x^3+5 x^2+7 x+35)\]HERE YOU GO \[2 (x+5) (x^2+7) \]
OpenStudy (anonymous):
D
OpenStudy (anonymous):
just regroup it , Try to combine those terms that have common then use common monomial . then factor it
OpenStudy (anonymous):
Wow. Seriously dude? Don't confuse him
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OpenStudy (anonymous):
YES! D
OpenStudy (anonymous):
thank you yeah I got confused but I got it now lol
OpenStudy (anonymous):
It cant be B @Jkaramali because you can factor it out more... \[2 x^3+10 x^2+14 x+70\]\[ (x^2 + 7)(2x + 10) \] WITH THE (2x + 10)
OpenStudy (anonymous):
Ah I see, my mistake.
OpenStudy (anonymous):
It koo! :)
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