Question

Find the 6 trig functions
P(-2square root of 5,-square root of 5)

Answer 1

so you have a point, two coordinates
\(\Large {\begin{matrix}
P\left(-\frac{2}{5}, \sqrt{5}\right)\\
&-\frac{2}{5}&\sqrt{5}\\
&x&y\\
&a& b
\end{matrix}}\)



to find "c", use the pythagorean theorem
once you have all 3 guys, "a", "b", and "c" then get all functions :)

Answer 2

hmm is negative "y", missed that there, so \(\Large \begin{matrix}
P\left(-\frac{2}{5}, \sqrt{5}\right)\\
&-\frac{2}{5}&-\sqrt{5}\\
&x&y\\
&a& b
\end{matrix}\)

Answer 3

woohoo, typos, anyhow, \(\Large \begin{matrix}
P\left(-\frac{2}{5}, -\sqrt{5}\right)\\
&-\frac{2}{5}&-\sqrt{5}\\
&x&y\\
&a& b
\end{matrix}\)

Answer 4

But how did you get -2over 5

Answer 5

\[\Large \begin{matrix} P\left(-2\sqrt{5}, -\sqrt{5}\right)\\ \end{matrix}\]

Answer 6

Yes @cinar but how do I find the third number and the six trig functions