Question

Which value(s) must be excluded as a value of x in the polynomial?
(x - 2 / (x2 - 25)

Answer 1

so division by 0 is not alowed right ? so you have to find for which values of x you have division by 0 means to solve \[x^{2}-25=0\] can u do that ?

Answer 2

lol no im stupid :/

Answer 3

i can try

Answer 4

nvm i basically forgot everything i learned this school year -,-

Answer 5

if u dont know something doesnt mean ur stupid cmon xD so we have
\[x^{2}-25=0\]
if we add 25 to boths side of the equation we would have
\[x^{2}-25+25=0+25\]
which is
\[x^{2}=25\]
now we have square root of both side and we have
\[\sqrt{x^{2}}=\sqrt{25}\]

Answer 6

aw thank you lol

Answer 7

do you know what values of x are excluded now ?

Answer 8

if i say no will you hate me lol?

Answer 9

no i will keep explaining until we get the answer :D

Answer 10

okay thank you

Answer 11

\[\sqrt{x^{2}}=\sqrt{25}\]
ok so we have that , you know that square root of \[\sqrt{x^{2}} =x\]
and \[\sqrt{25}=5\]
so we get x=5 BUT we need to include x=-5 because \[(-5)^{2}=25\]
so our final answer is x=5 and x=-5 should be excluded

Answer 12

so the final answer is x=5 ?

Answer 13

and x=-5

Answer 14

both are ur answer

Answer 15

okay tysm :)!

Answer 16

no problem