Question I'm confused about...

What is the oxidation state for the atoms in the reaction:
2Al + 8H2O → 2H+1 + 3H2 + 2Al(OH)4-1
a) Elemental aluminum (Al)
b) One hydrogen atom in H2O
c) One oxygen atom in H20
d) Elemental hydrogen (H)
e) One aluminum atom in Al(OH)4-1
f) One oxygen atom in Al(OH)4-1
g) One hydrogen atom in Al(OH)4-1

Question

Question I'm confused about...


What is the oxidation state for the atoms in the reaction:
2Al + 8H2O → 2H+1 + 3H2 + 2Al(OH)4-1 
a) Elemental aluminum (Al)
b) One hydrogen atom in H2O 
c) One oxygen atom in H20 
d) Elemental hydrogen (H) 
e) One aluminum atom in Al(OH)4-1 
f) One oxygen atom in Al(OH)4-1 
g) One hydrogen atom in Al(OH)4-1

chmvijay · Answer

what u think the answers would be ?

anonymous · Answer

How do I calculate oxidation states for this reaction? Can you please give me an example?

chmvijay · Answer

Oxygen has negative - charge Hydrogen is having +ve charge 
elements will always have zero charge

chmvijay · Answer

|dw:1376360908124:dw|