help with optimization! (attached)
okay i understand everything..... except how to find the minimum!
are you familiar with derivative?
i know they got the equation. y=6x+(21000/x)
yes
then after i'm not sure how they got: Minimum occurs at 59.16 ft for the length (found on a graphing calc) width: 10500/59.16 = 177.5 ft Perimeter = 710 ft
ok, well the method they got the minimum is just by using a graphing calculator with a max min function on it doing it manually would involve finding the first derivative of the equation and then setting it equal to zero and then solving for L
or x
is there a way to do that without it?
without the graphing calculator? or without having to do it manually?
by hand
no calculator
by hand would involve finding the first derivative of the equation and then setting it equal to zero and then solving for L
because the slope at the minimum point is zero
can you show me?
im doing it wrong, even on calculator :/ I'm not getting it.
\[y = \frac{21000}{x} + 6x\] \[y' = -\frac{21000}{x^2} +6\] \[y' =0\] \[0=-\frac{21000}{x^2} +6\] solve for x hopefully i didnt screw up the derivative
\[\frac{1}{x} = x^{-1}\]
any questions?
@completeidiot derivative is fine :3
yeah 1/x?
im just pointing out the identity that allows you to use the "power" rule for derivatives
\[y= x^n\] \[y' = nx^{n-1}\]
im not getting that. i got up to here: y=6-21000/x^2 then set it to 0
then im lost
1/x is not part of the problem you can ignore it if you want its just that the identity is sometimes not obvious to other people
once you set it equal to zero 0=6-21000/x^2 just solve for x
6= 21000/x^2 x^2= 21000/6 x = sqrt {21000/6}
any other questions? sorry for any confusion i may have caused
i got it=]
thanks!
no problem
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