How to graph the circle (x+2) ^2 + (y+1)^2=32

Question

psymon · Answer

So the equation of a circle is:
$$(x-h)^{2}+ (y-k)^{2} = r ^{2}$$h is the x-coordinate of the center and k is the y-coordinate of the center. Notice how I put minus signs in the equation. These must be minus signs. If you ever see a plus sign there, it means the number is actually negative. So since you have a +2 and a +1, this means you actually have this:
$$(x-(-2))^{2}+(y-(-1))^{2} = 32$$
So because of that, your center is at the point (-2,-1). Now the equation also says that 32 equals r^2. So in order to know how far out from the center of the circle to go, just take the square root of 32. With that info, you should be able to graph it :3

anonymous · Answer

Where I get lost is the square-root of 32 is 5.656854

psymon · Answer

Sounds about right. Just means you have to approximate. So you'd graph somewhere around 5.5 ish.

anonymous · Answer

so would some points be -2,4.5 and 3.5,-1

anonymous · Answer

and why wouldnt i round to 6

anonymous · Answer

@Psymon

psymon · Answer

Well, you normally wouldn't round. If you round, then that might be becauseof specific instructions given. So you could have (-7.5,-1), (3.5, -1), (-2,-6.5), (-2, 4.5). That's what I'd try and do and then just draw it.

anonymous · Answer

Thank you soooo much!!!

psymon · Answer

Yep, yep ^_^