Question

To solve the problem BELOW, find the angle in the interval [ -π/2 , π/2 ] whose tangent equals 0.

Answer 1

\[\tan^{-1}(\cos \frac{ π }{ 2 })\]

Answer 2

I know that cos(π/2) = 0º

Answer 3

So what angle does tan = 0?

Answer 4

Does that mean:\[\tan^{-1}(0) = 0\]

Answer 5

You said what angle...\[\tan(0º) = 0\]

Answer 6

Right, 0, lol.

Answer 7

Wow, thats it? I thought there would be more to the problem...

Answer 8

@radar @genius12 @amistre64 @phi Psymon is offline now, and I kinda fell asleep before I asked him, but is that all to my problem?

Answer 9

cos(pi/2) = 0

tan(0) is 0

you should know the sin,cos,tan of special angles 0,30,45,60 and 90 degrees

Answer 10

knowing
tan(0)= 0
you also know
\[ \tan^{-1}(\tan(0))= \tan^{-1}(0) \\ 0 = \tan^{-1}(0) \\ \tan^{-1}(0)=0\]

Answer 11

Gotcha!

Answer 12

cos pi/2 is a ratio, not an angle

\(tan^{-1}(0^o)\) has no meaning since inverse function take a ratio and give back an angle

Answer 13

Makes more sense now :) Thanks!