Question

Part 1: Fill in the missing row of the truth table.
Part 2: Are the two statements logically equivalent? Why or why not?

~(p ∧ q) and (p ∨ ~q)

Answer 1

Part 1: F T F F T F F is what I got for Part 1

Answer 2

My question is for Part 2 which part of the truth table should I be using?

Answer 3

Assuming that weird a.ss squigle denotes logical negation, then no they are not equivilent using de-morgans rules.

Answer 4

Which row of the table are we supposed to be using?

Answer 5

Do all four of those have to be true to be true?

Answer 6

im not looking at your truth table, you do the work

Answer 7

I did

Answer 8

I want to know how its supposed to be logically equivalent

Answer 9

i told you already there not

Answer 10

HOW

Answer 11

Emphasize on the how

Answer 12

~(p^q) = ~p v ~q

Answer 13

this is easily provable and is called DeMorgans law

Answer 14

I'm lost

Answer 15

I know that its two false and two true

Answer 16

you are filling in the mimssing row
F T F F T F T

Answer 17

No I mean for ~(p ∧ q) and (p ∨ ~q)

Answer 18

<--> means iff not and

Answer 19

I know

Answer 20

I understand