Question

Could someone please explain to me step by step how to solve equations like this please

Find x if
2x(squared sign) - 5x + 3 = 0

Answer 1

2x^2 -2x-5x+3=0
when middle term is split

Answer 2

sorry

Answer 3

it is 2x^2 -2x-3x+3

Answer 4

Or you can use completing the square or quadratic formula, if you have learnt those methods

Answer 5

then it becomes
2x(x-1)-3(x-1)

Answer 6

which will be
(2x-3)(x-1)=0

Answer 7

2x-3=0 and x-1=0

Answer 8

x=3/2 or x=1

Answer 9

@lisamc91 did you understand?

Answer 10

yes I do thanks allot! :)

Answer 11

you're welcome

Answer 12

ill show you the quadratic formula method...

Answer 13

Say you have some general quadratic equation
\[ax^2+bx+c=0\]

The solution(s) for x, can be found using
the quadratic formula
\[x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

With the solution(s), you can factorise the original quadratic
\[(x-x_1)(x-x_2)=0\]

Answer 14

so for your example
\[2x^2 - 5x + 3 = 0\]
comparing with \[ax^2+bx+c=0\]
\[a=2,\qquad b=-5,\qquad c=3\]

Answer 15

so
\[x_{1,2}=\frac{-(-5)\pm\sqrt{(-5)^2-4\times2\times3}}{2\times2}\]
______________________

ie one solution for x
\[x_1=\frac{-(-5)+\sqrt{(-5)^2-4\times2\times3}}{2\times2}\]
and the other
\[x_2=\frac{-(-5)-\sqrt{(-5)^2-4\times2\times3}}{2\times2}\]

Answer 16

are you following @lisamc91 ?

Answer 17

ah yes the formula really helped! Ive done a few with the formula i think im getting it now! thank you unklerhaukus! :)

Answer 18

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